Construct a tangent to a circle of radius 4cm from a point which is at a distance of 6cm from its center.
OR
Steps of construction
1. Draw a circle of radius 4 cm.
2. Join OM’ and bisect it. Let M be mid – point of OM’.
3. Taking M as center and MO as radius draw a circle to intersect circle (0, 4) at two points P and Q.
4. Join PM’ and QM’. PM’ and QM’ are the required tangents from M’ to circle C (0, 4).
OR
Step1: Draw circle of radius 6cm with center A, mark
point C at 10 cm from the center.
Step 2: find perpendicular bisector of AC
Step3: Take this point as center and draw a circle through A and C
Step4:Mark the point where this circle intersects our circle and draw tangents through C
Length of tangents = 8cm
AE is perpendicular to CE (tangent and radius relation)
In ΔACE
AC becomes hypotenuse
AC2 = CE2 + AE2
102 = CE2 + 62
CE2 = 100-36
CE2 = 64
CE = 8cm