How many moles of calcium carbonate (CaCO3) are present in 10 g of the substance? (Ca = 40 u; C = 12 u; O = 16 u)
Molar mass of calcium carbonate (CaCO3) = 40+12+48 = 100g
Mass of the substance = 10g
As we know that, Number of moles = mass of an element/molar mass of an element
Hence Number of moles = 10/100 = 0.1 mole.