Calculate the number of moles present in a drop of chloroform (CHCl 3 ) weighing 0.0239 g. (Atomic masses: C = 12 u; H = 1 u; Cl = 35.5 u)

Question

Philoid · Accepted Answer

Molar mass of chloroform (CHCl₃) = (12+1+3x35.5) = 119.5g

Given Mass of the chloroform (CHCl₃) = 0.0239g

As we know that, Number of moles = mass of an element/molar mass of an element

Hence Number of moles of chloroform (CHCl₃) = 0.0239g/119.5g = 0.0002 moles.