If 1 gram of sulphur dioxide contains x molecules, how many molecules will be present in 1 gram of oxygen?
(S = 32 u; O = 16 u)
1 mole of SO2 = Mass of S + 2 × Mass of O = 64 grams
64 g of SO2 = 1 mole
So, 1 g of SO2 = 1/64 mole
Now since equal moles of all the substances contain equal number of molecules so, 1/64 mole of O2 will also contain x molecules like SO2.
32 g of oxygen = 1 mole
So, 1 g of oxygen = 1/32 mole
Now, 1/64 mole of oxygen contains = x molecules
So, 1/32 mole of oxygen will contain = x × 64/32 = 2x molecules