Ifx3-3x2+3x-7=(x+1)(ax2+bx+c), then a+b+c=
We have,
= 
=
= 
By compairing both sides ,
= a = 1
= a + b = -3
= b + c = 3
= c = -7
Thus , a + (b + c) = 1+3 = 4.
13
Ifx3-3x2+3x-7=(x+1)(ax2+bx+c), then a+b+c=
We have,
=
=
=
By compairing both sides ,
= a = 1
= a + b = -3
= b + c = 3
= c = -7
Thus , a + (b + c) = 1+3 = 4.