If x = 2 is a root of the polynomial f (x)= 2x2-3x+7a, find the value of a.
We have,
f (x) = 2x2 – 3x + 7a
Put x = 2
f (2) = 2 (2)2 – 3 (2) + 7a
= 2 * 4 – 6 + 7a
= 8 – 6 + 7a
= 2 + 7a
Given, x = 2 is a root of f (x) = 2x2 – 3x + 7a
f (2) = 0
Therefore, 2 + 7a = 0
7a = -2
a = 
3