In each of the following, using the remainder theorem, find the remainder when f(x) is divided by g(x):

f(x) = x3+4x2-3x+10, g(x) = x+4

We have,

f(x) = x3+4x2-3x+10 and g (x) = x + 4


Therefore, by remainder theorem when f (x) is divided by g (x) = x – (-4), the remainder is equal to f (-4)


Now, f(x) = x3+4x2-3x+10


f (-4) = (-4)3 + 4 (-4)2 – 3 (-4) + 10


= -64 + 4 * 16 + 12 + 10


= 22


Hence, required remainder is 22.


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