If the polynomials ax3+3x2-13 and 2x3-5x+a when divided by (x-2) leave the same remainder, find the value of a.

Let p (x) = ax3+3x2-13 and q (x) = 2x3-5x+a be the given polynomials.

The remainders when p (x) and q (x) are divided by (x – 2) and p (2) and q (2) respectively.


By the given condition, we have:


p (2) = q (2)


a (2)3 + 3 (2)2 – 13 = 2 (2)3 – 5 (2) + a


8a + 12 – 13 = 16 – 10 + a


7a – 7 = 0


7a = 7


a =


= 1


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