Using factor theorem, factorize each of the following polynomial:

x3-10x2-53x-42

Let, f (x) = x3-10x2-53x-42

The factors of the constant term – 42 are


Putting x = - 1, we have


f (-1) = (-1)3 – 10 (-1)2 – 53 (-1) - 42


= -1 – 10 + 53 - 42


= 0


So, (x + 1) is a factor of f (x)


Let us now divide


f (x) = x3-10x2-53x-42 by (x + 1) to get the other factors of f (x)


Using long division method, we get


x3-10x2-53x-42 = (x + 1) (x2 – 11x – 42)


x2 – 11x - 42 = x2 – 14x + 3x - 42


= x (x – 14) + 3 (x – 14)


= (x – 14) (x + 3)


Hence, x3-10x2-53x-42 = (x + 1) (x - 14) (x + 3)


11