Using factor theorem, factorize each of the following polynomial:
2y3-5y2-19y+42
Let, f (y) = 2y3-5y2-19y+42
The factors of the constant term + 42 are
Putting y = 2, we have
f (2) = 2 (2)3 – 5 (2)2 – 19 (2) + 42
= 16 – 20 - 38 + 42
= 0
So, (y - 2) is a factor of f (y)
Let us now divide
f (y) = 2y3-5y2-19y+42 by (y - 2) to get the other factors of f (x)
Using long division method, we get
2y3-5y2-19y+42 = (y - 2) (2y2 – y – 21)
2y2 – y - 21 = (y + 3) (2y – 7)
Hence, 2y3-5y2-19y+42 = (y - 2) (2y - 7) (y + 3)