Using factor theorem, factorize each of the following polynomial:
x3-2x2-x+2
Let, f (x) = x3-2x2-x+2
The factors of the constant term +2 are
Putting x = 1, we have
f (1) = (1)3 – 2 (1)2 – (1) + 2
= 1 – 2 – 1 + 2
= 0
So, (x - 1) is a factor of f (x)
Let us now divide
f (x) = x3-2x2-x+2 by (x - 1) to get the other factors of f (x)
Using long division method, we get
x3-2x2-x+2 = (x - 1) (x2 - x - 2)
x2 - x - 2 = x2 - 2x + x - 2
= x (x - 2) + 1 (x - 2)
= (x + 1) (x - 2)
Hence, x3-2x2-x+2 = (x - 1) (x + 1) (x - 2)
= (x - 1) (x + 1) (x – 2)