If x3+6x2+4x+k is exactly divisible by x+2, then k =
Since, x+2 is exactly divisible by f(x)
Means x+2 is a factor of f (x), so
f (-2) = 0
(-2)3 + 6 (-2)2 +4 (-2) + k = 0
-16 + 24 + k = 0
k= - 8