If x+2and x-1 are the factors of x3+10x2+mx+n, then the value of m and n are respectively
Let f (x) = x3+10x2 +mx + n
Since, (x + 2) and (x - 1) are factor of f (x)
So, f (-2) = 0
(-2)3 + 10 (-2)2 + m (-2) + n
32 - 2m + n = 0 (i)
f (1) = 0
(1)3 + 10 (1)2 + m (1) + n = 0
11 + m + n = 0 (ii)
(2) - (1)
3m -21 = 0
m = 7 (iii)
Using (iii) and (ii), we get
11 + 7 + n= 0
n = - 18