Given that,

Two supplementary angles are differ by 48^o

Let, the angle measured be x^o

Therefore, its supplementary angle will be (180^o – x)

It is given that,

(180^o – x) – x = 48^o

2x = 180^o – 48^o

x = 66^o

Hence, 180^o – x = 114^o

Therefore, angles are 66^o and 114^o.