In Fig. 8.35, ∠AOC and ∠BOC form a linear pair. If a -2b = 30°, find a and b.
Given,
If (a – 2b) = 30o
∠AOC = a
∠BOC = b
Therefore,
a + b = 180o (i)
Given,
(a – 2b) = 30o (ii)
Now,
Subtracting (i) and (ii), we get
a + b – a + 2b = 180o – 30o
b = 50o
Hence,
(a – 2b) = 30o
a – 2 (50) = 30o
a = 130o