In Fig. 8.35, AOC and BOC form a linear pair. If a -2b = 30°, find a and b.

Given,

If (a – 2b) = 30o


AOC = a


BOC = b


Therefore,


a + b = 180o (i)


Given,


(a – 2b) = 30o (ii)


Now,


Subtracting (i) and (ii), we get


a + b – a + 2b = 180o – 30o


b = 50o


Hence,


(a – 2b) = 30o


a – 2 (50) = 30o


a = 130o


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