In Fig. 8.62, lines AB and CD intersect at O. If AOC + BOE = 70° and BOD = 40° find BOE and reflex COE.

Given that,

AOC + BOE = 70o


And,


BOD = 40o


BOF =?


BOD = AOC = 40o (Vertically opposite angle)


Given,


AOC + BOE = 70o


40o + BOE = 70o


BOE = 70o – 40o


= 30o


AOC and BOC are linear pair angle


AOC + COE + BOE = 180o


COE = 180o – 30o – 40o


= 110o


Therefore,


COE = 360o – 110o


= 250o


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