In Fig 8.109, if AB ||CD and CD||EF, find ACE.

Since,

EF CD


Therefore,


EFC + LEC = 180o(Co. interior angles)


ECD = 180o – 130o


= 50o


Also, BA CD


BAC = ACD = 70o(Alternate angles)


But, ACE + ECD = 70o


ACE = 70o -50o


=20o


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