The opposite sides of a quadrilateral are parallel. If one angle of the quadrilateral is 60° find the other angles.
AB ‖ CD and AD is transversal
AD ‖ BC
Therefore,
∠A + ∠D = 180o(Co. interior angles are supplementary)
60o + ∠D = 180o
∠D = 120o
Now,
AD ‖ BC and AB is transversal
∠A + ∠B = 180o(Co. interior angles are supplementary)
60o + ∠B = 180o
∠B = 120o
Hence,
∠A = ∠C = 60o
∠B = ∠D = 120o