In Fig 8.120, arms BA and BC of ∠ABC are respectively parallel to arms ED and EF of ∠DEF. Prove that ∠ABC = ∠DEF.
Given that,
AB ‖ DE and EC ‖ EF
To prove: ∠ABC = ∠DEF
Construction: Produce BC to X such that it intersects DE at M
Proof: Since, AB ‖ DE and BX is the transversal
Therefore,
∠ABC = ∠DMX (Corresponding angles) (i)
Also,
BX ‖ EF and DE is transversal
Therefore,
∠DMX = ∠DEF (Corresponding angles) (ii)
From (i) and (ii), we get
∠ABC = ∠DEF
Hence, proved