In Fig. 8.137, if AB|| HF and DE||FG, then the measure of ∠FDE is
Given that,
AB ‖ HF and CD cuts them
∠HFC = ∠FDA (Corresponding angle)
∠FDA = 28o
∠FDA + ∠FDE + ∠EDB = 180o (Linear pair)
28o + ∠FDE + 72o = 180o
∠FDE = 80o