Given that,

AB ‖ CD

Produce P to Q so that PQ ‖ AB ‖ CD

∠BAP + ∠APQ = 180^o (Interior angle)

132^o + ∠APQ = 180^o

∠APQ = 48^o (i)

∠APC = ∠APQ + ∠QPC

148^o = 48^o + ∠QPC [From (i)]

∠QPC = 100^o

∠QPC + ∠PCD = 180^o (Interior angles)

100^o + ∠PCD = 180^o

∠PCD = 80^o

∠PCD + x = 180^o (Linear pair)

80^o + x = 180^o

x = 100^o