Find one irrational number between 0.2101 and 0.2222 ….= .

Let a = 0.2101

And, b = 0.2222….


We observe that the second decimal place a has digit 1 and b has digit 2, therefore, a < b. In the third decimal place a has digit 0. So, if we consider irrational number


x = 0.211011001100011…


We find that,


a < x < b


Hence, x is required irrational number.


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