Find two irrational numbers lying between 0.1 and 0.12.

Let, a = 0.1 = 0.10

And, b = 0.12


We observe that in the second decimal place a has digit 0 and b has digit 2. Therefore a < b. So, if we consider irrational numbers


x = 0.11011001100011…


y = 0.111011110111110…


We find that,


a < x < y < b


Hence, x and y are required irrational numbers.


12