The angles of a triangle are arranged ascending order of magnitude. If the difference between two consecutive angles is 10°, find the three angles.

Given that,

The difference between two consecutive angles is 10o.


Let, x, x + 10 and x + 20 be the consecutive angles differ by 10o.


We know that,


x + x + 10 + x + 20 = 180o


3x + 30o = 180o


3x = 180o – 30o


3x = 150o


x = 50o


Therefore, the required angles are:


x = 50o


x + 10 = 50o + 10o


= 60o


x + 20 = 50o + 20o


= 70o


The difference between two consecutive angles is 10o then three angles are 50o, 60o and 70o.


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