The angles of a triangle are arranged ascending order of magnitude. If the difference between two consecutive angles is 10°, find the three angles.
Given that,
The difference between two consecutive angles is 10o.
Let, x, x + 10 and x + 20 be the consecutive angles differ by 10o.
We know that,
x + x + 10 + x + 20 = 180o
3x + 30o = 180o
3x = 180o – 30o
3x = 150o
x = 50o
Therefore, the required angles are:
x = 50o
x + 10 = 50o + 10o
= 60o
x + 20 = 50o + 20o
= 70o
The difference between two consecutive angles is 10o then three angles are 50o, 60o and 70o.