Two angles of a triangle are equal and the third angle is greater than each of those angles by 30°. Determine all the angles of the triangle.

Question

Two angles of a triangle are equal and the third angle is greater than each of those angles by 30&#xB0;. Determine all the angles of the triangle.

Philoid · Accepted Answer

Given that,

Two angles are equal and third angle is greater than each of those angles by 30^o.

Let, x, x, x + 30^o be the angles of the triangle.

We know that,

Sum of all angles of triangle is 180^o

x + x + x + 30^o = 180^o

3x + 30^o = 180^o

3x = 180^o – 30^o

3x = 150^o

x = 50^o

Therefore,

The angles are:

x = 50^o

x + 30^o = 50^o + 30^o

= 80^o

Therefore, the required angles are 50^o, 50^o, 80^o.