In Fig. 9.39, AB||DE. Find ACD.

Since,

AB DE


ABC = CDE (Alternate angles)


ABC = 40o


In


A + B + ACB = 180o


30o + 40o + ACB = 180o


ACB = 180o – 70o


= 110o (i)


Now,


ACD + ACB = 180o (Linear pair)


ACD + 110o = 180o [From (i)]


ACD = 180o – 110o


= 70o


Hence, ACD = 70o.


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