In Δ ABC, if bisectors of ABC and ACB intersect at O angle of 120°, then find the measure of A.

In

BOC + OBC + OCB = 180o


120o + B + C = 180o


(B + C) = 60o


B + C = 120o (i)


In


A + B + C = 180o


A + 120o = 180o [From (i)]


A = 60o


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