In Δ ABC , if ∠ A = 100° AD bisects ∠ A and AD ⊥ BC. Then, ∠ B =

Question

In &#x394; ABC , if &#x2220; A = 100&#xB0; AD bisects &#x2220; A and AD &#x22A5; BC. Then, &#x2220; B =

Philoid · Accepted Answer

Given,

AD perpendicular to BC

∠A = 100^o

In ,

∠ADB + ∠B + ∠DAC = 180^o

90^o + ∠B + ∠A = 180^o

∠B + * 100^o = 180^o – 90^o

∠B + 50^o = 90^o

∠B = 40^o