The side BC of Δ ABC is produced to a point D. The bisector of ∠A meets side BC in L, If ∠ABC = 30° and ∠ACD = 115°, then ∠ALC =
Given,
∠ABC = 30o
∠ACD = 115o
By exterior angle theorem,
∠ACD = ∠A + ∠B
115o = ∠A + 30o
∠A = 85o
∠ACD + ∠ACL = 180o (Linear pair)
∠ACL = 65o
In
∠ALC + ∠LAC + ∠ACL = 180o
∠ALC + ∠A + 65o = 180o
∠ALC = 72.5o