By exterior angle theorem,

In

∠OCA + ∠AOC = x

x = 80^o + 40^o

= 120^o

∠AOC = ∠DOB (Vertically opposite angle)

∠DOB = 40^o

By exterior angle theorem,

In

y = ∠BOD + ∠ODB

= 40^o + 70^o

= 110^o

Now, x + y = 230^o