In Fig. 9.45, if AB ⊥ BC, then x =
Given,
AB is perpendicular to BC so ∠B = 90o
∠CED = 32o (Vertically opposite angles)
In
∠BDE + ∠BED + ∠DBE = 180o
x + 14o + 32o + x + 90o = 180o
2x = 44o
x = 22o