In Fig. 9.47, for which value of x is l1 || l2?
Since,
l1‖ l2
And,
AB cuts them so,
∠DBA = ∠BAE = 78o
∠BAC + 35o = 78o
∠BAC = 43o
In
∠BAC + ∠ABC + ∠ACB = 180o
43o + x + 90o = 180o
x = 47o