The base BC of triangle ABC is produced both ways and the measure of exterior angles formed are 94° and 126°. Then, BAC=

Given,

ABD = 94o and


ACE = 126o


ABD + ABC = 180o (Linear pair)


ABC = 86o (i)


ACE + ACB = 180o (Linear pair)


ACB = 54o (ii)


In


ABC + ACB + BAC = 180o


86o + 54o + BAC = 180o


BAC = 40o

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