In Fig. 10.25, AB = AC and DB = DC, find the ratio ∠ABD:∠ACD.
Consider the figure,
Given,
AB = AC
DB = DC
To find: Ratio ∠ABD =∠ACD
Now, are isosceles triangles
Since, AB = AC
And,
DB = DC
Therefore, ∠ABC = ∠ACB and,
∠DBC = ∠DCB (Angle opposite equal sides)
Now, consider ∠ABD: ∠ACD
(∠ABC - ∠DBC): (∠ACB - ∠DCB)
(∠ABC - ∠DBC): (∠ABC - ∠DBC) [Since, ∠ABC = ∠ACB and ∠DBC = ∠DCB]
1: 1
Therefore, ∠ABD: ∠ACD = 1:1