In Fig. 10.92, it is given that AB = CD and AD = BC. Prove that Δ ADC ≅ Δ CBA.
Given, in the figure
AB = CD
And,
AD = BC
To prove: Δ ADC ≅ Δ CBA
Proof: Consider,
AB = CD (Given)
BC = AD (Given)
AC = AC (Common)
By SSS theorem,
Δ ADC ≅ Δ CBA
Hence, proved