In Δ ABC, if A=40° and B=60°. Determine the longest and shortest sides of the triangle.

Given that in Δ ABC

A = 40o and B = 60o


We have to find shortest and longest side.


We know that,


Sum of angles of triangle = 180o


A + B + C = 180o


40o + 60o + C = 180o


100o + C = 180o


C = 180o – 100o


= 80o


Now,


40o < 60o < 80o


A < B < C


C is greater angle and A is smaller angle.


As, A < B < C


BC < AC < AB (Therefore, side opposite to greater angle is larger and side opposite to smaller angle is smaller)


Therefore, AB is longest and BC is smallest or shortest side.


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