In Fig. 10.134, if AB = AC and ∠B = ∠C. Prove that BQ = CP.
Given,
∠B = ∠C
AB = AC
To Prove: BQ = CP
Proof: In ABQ and ACP
∠B = ∠C (Given)
AB = AC (Given)
∠A = ∠A (Common)
Hence, by A.S.A. Theorem
ABQ ACP
BQ = CP (By c.p.c.t)