In a Δ ABC, if AB = AC and BC is produced to D such that ∠ACD =100°, then ∠A =
∠ACB + ∠ACD = 180°
On solving we get,
∠ACB = 80°
∠ABC = ∠ACB = 80° (Angles opposite to equal sides are equal)
In ABC,
∠A + ∠B + ∠C= 180°
∠A + 80° + 80° = 180°
∠A = 20°