In Fig. 10.139, ABC is an isosceles triangle whose side AC is produced to E. Through C, CD is drawn parallel to BA. The value of x is
∠B = ∠C (Angles opposite to equal sides are equal)
In ABC,
∠A + ∠B+ ∠C= 180°
∠A = 76°
Now,
∠BAC= ∠ACD (Alternate angles)
∠ACD = 76°
Now,
∠ACD + ∠ECD= 180°
x = 180- 76°
x = 104°