In a Δ ABC, AB = 15 cm, BC = 13 cm and AC = 14 cm. Find the area of ΔABC and hence its altitude on AC.
Let a, b and c are the sides of triangle and s is the semi-perimeter, then its area is given by:
A = 
where 
[Heron’s Formula]
= 
= 21
A = 
A = 
= 
cm2
Area of triangle = 
84 = 
Altitude = 12 cm
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