Two parallel side of a trapezium are 60 cm and 77 cm and other sides are 25 cm and 26 cm. Find the area of the trapezium.

Let ABCD is a trapezium in which AB = 77 cm, BC = 26 cm, CD = 60 cm, DA = 25 cm


Draw CE// AD


Now, ACDE is a parallelograme


BE = AB-DC = 77-60 = 17 cm


In ∆BEC, Let a, b and c are the sides of triangle and


And s be the semi-perimeter, then its area


A = where



= = 34


A=


A = = m2


Therefore area of ∆BCE =


204 × 2 = 17× Altitude


Altitude = 24 cm


Area of trapezium ABCD = =



Therefore area of trapezium ABCD = 1644 cm2


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