Two parallel side of a trapezium are 60 cm and 77 cm and other sides are 25 cm and 26 cm. Find the area of the trapezium.
Let ABCD is a trapezium in which AB = 77 cm, BC = 26 cm, CD = 60 cm, DA = 25 cm
Draw CE// AD
Now, ACDE is a parallelograme
BE = AB-DC = 77-60 = 17 cm
In ∆BEC, Let a, b and c are the sides of triangle and
And s be the semi-perimeter, then its area
A = where
=
= 34
A=
A = =
m2
Therefore area of ∆BCE =
204 × 2 = 17× Altitude
Altitude = 24 cm
Area of trapezium ABCD = =
⇒
Therefore area of trapezium ABCD = 1644 cm2