If the area of an isosceles right triangle is 8 cm, what is the perimeter of the triangle?
In right isosceles ∆ABC
Area of triangle = 
8 = 
(AC)2 = (AB)2 + (BC)2
Perimeter of ∆ABC = AB + BC + CA = 4 + 4 + 4√2 = 8 + 4√2 cm
8
If the area of an isosceles right triangle is 8 cm, what is the perimeter of the triangle?
In right isosceles ∆ABC
Area of triangle =
8 =
(AC)2 = (AB)2 + (BC)2
Perimeter of ∆ABC = AB + BC + CA = 4 + 4 + 4√2 = 8 + 4√2 cm