In figure 12.35, the ratio of AD to DC is 3 to 2. If the area of ΔABC is 40 cm2, what is the area of ΔBDC?
In ∆ABC
AD:DC = 3:2
Area of ∆ABD = =
Area of ∆BDC = =
Area of ∆ABC = area of ∆ABD+ area of ∆BDC = 40 cm2
Therefore area of ∆ABD =
Therefore area of ∆BDC =