Find the greatest number that will divide 445, 572 and 699 leaving remainder 4, 5 and 6 respectively.

The new numbers after subtracting remainders are:


445-4 = 441


572-5 = 567


699-6 = 693


Prime factors of 441= 3 × 3 × 7 × 7


Prime factors of 567 = 3 × 3 × 3 × 3 × 7


Prime factors of 693 = 3 × 3 × 7 ×11


Therefore HCF of 441, 567 and 693 is: 3 x 3 x7 = 63


Hence the greatest number that will divide 445, 572 and 699 leaving remainder 4, 5 and 6 respectively is 63


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