A merchant has 120 litres of oil of one kind, 180 litres of another kind and 240 litres of third kind. He wants to sell the oil by filling the three kinds of oil in tins of equal capacity. What should be the greatest capacity of such a tin?
To find greatest capacity of tin we should find HCF of 120 and 180 and 240
Prime factors of 120= 2 × 2 × 2 × 3 × 5
Prime factors of 180 = 2 × 2 × 3 × 3 × 5
Prime factors of 240 = 2 × 2 × 2 × 2 × 3 × 5
Therefore HCF of 120, 180 and 240 is: 2 × 2 × 3 × 5 = 60
Therefore the greatest capacity of a tin is 60 Liters