Two brands of chocolates are available in packs of 24 and 15 respectively. If I need to buy an equal number of chocolates of both kinds, what is the least number of boxes of each kind I would need to buy?
To find the least number of boxes of each kind, we need to find LCM of 24 and 15
Prime factors of 24 = 2 × 2 × 2 × 3
Prime factors of 15 = 3 × 5
Therefore LCM of 24 and 15 is: 2 × 2 × 2 × 3 × 5 = 120
Number of colour pencil packs = 
= 5
Number of crayons packs = 
= 8
Hence 5 boxes of first brand and 8 boxes of second kind need to buy.
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