If D and E are points on sides AB and AC respectively of a such that and BD = CE. Prove that is isosceles.

We have DEBC


by the converse of proportionality theorem


AD/DB=AE/EC


AD/DB=AE/DB [BD=CE]


AD=AE


Adding D both sides


AD+BD=AE+DB


AD+BD=AE+EC [BD=CE]


AB=AC


ABC is isosceles


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