D is the mid-point of side BC of a . AD is bisected at the point E and BE produced cuts AC at the point X. Prove that BE : EX = 3 : 1.

Given:- In ΔABC, D is the midpoint of BC and E is the midpoint of AD.


To prove:- BE: EX = 3 : 1


Const:- Through D, Draw DF||BX


Prof:- In ΔEAX and Δ ADF


<EAX = <ADF (Common)


<AXE = <DAF (Corresponding angles)


Then, ΔEAX ~ Δ ADF


So, (Corresponding parts of similar triangle are proportion)


Or, (AE = ED given)


Or, DF = 2EX. ……………(i)


In ΔCDF and ΔCBX (By AA similarity)


SO, (Corresponding parts of similar triangle area proportion)


Or (BD = DC given)


Or BE + EX = 2DF


Or BE = EX = 4EX


Or BE = 4EX – EX


Or BE = 4EX – EX


Or BE = 3EX


Or BE/EX =3/1


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