If and
are two right triangles, right angled at B and M respectively such that
. Prove that
(i)
(ii)
We have,
<B = <M = 90°
And, <BAC = <MAP
In ΔABC and ΔAMP
<B = <M (each 90°)
<BAC = <MAP (Given)
Then, ΔABC ~ΔAMP (By AA similarity)
So, CA/PM = BC/MP(Corresponding parts of similar triangle are proportional)