If and are two right triangles, right angled at B and M respectively such that . Prove that

(i)


(ii)

We have,


<B = <M = 90°


And, <BAC = <MAP


In ΔABC and ΔAMP


<B = <M (each 90°)


<BAC = <MAP (Given)


Then, ΔABC ~ΔAMP (By AA similarity)


So, CA/PM = BC/MP(Corresponding parts of similar triangle are proportional)


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