ABC is a triangle in which 
= 90°, 
, BC = 12 cm and AC = 5 cm. Find the ratio of the areas of 
.
In Δ ANC and Δ ABC
<C = <C (Common)
<ANC = <BAC (Each 90°)
Then, Δ ANC ~ Δ ABC (By AA similarity)
By area of similarity triangle theorem.
Area of ΔABC/Area of ΔPQR = AC2 /BC2
Or, 52/122
Or, 25/144
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